Questions
The angle between the vectors 2i+3j+k and -3i+6k is
a
0°
b
45°
c
60°
d
90°
detailed solution
Correct option is D
cosθ=A⋅BABA.B = (2 i + 3j - k) . (- 3i + 6 k)=2(-3)+3(0) +1(6) = 0∴cosθ=014×45=0 or θ=90∘Talk to our academic expert!
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