The angle of incidence for a ray of light at a refracting surface of a prism is 450. The angle of prism is 600. If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are

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45°;2

30°;12

45°;12

30°;2

answer is D.

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Detailed Solution

Given, i=45°,A=60° Since the ray undergoes minimum deviation, therefore, angle of emergence from second face, e=i=45°∴δm=i+e-A=45°+45°-60°=30°μ=sin(A+δm2)sin(A2)=2

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