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Questions  

The angle of minimum deviation by prism is (180°–2A). Its critical angle will be

a
sin-1tanA2
b
sin-1cotA2
c
cos-1cotA2
d
cos-1tanA2

detailed solution

Correct option is A

μ=sinA+180-2A2sin A/2 ; μ=cotA2 μ=1sin c ; 1sin c=cot A2⇒c=sin-1tanA2

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