The angle of minimum deviation by prism is (180°–2A). Its critical angle will be
sin-1tanA2
sin-1cotA2
cos-1cotA2
cos-1tanA2
μ=sinA+180-2A2sin A/2 ; μ=cotA2 μ=1sin c ; 1sin c=cot A2⇒c=sin-1tanA2