Angle of minimum deviation for a prism of refractive index 1.5 is equal to the angle of prism. The angle of prism is (cos 41° = 0.75)
62°
41°
82°
31°
By prism formula n=sinA+A2sinA2=2sinA2cosA2sinA2 ∴cosA2=n2=1.52=0.75=cos41∘⇒A=82∘