First slide

Diffraction of light-Wave Optics

Question

The angle of polarization for a medium is 60^o, what will be critical angle for this

Moderate

A

$\sin^{- 1} \sqrt{3}$
B

$\tan^{- 1} \sqrt{3}$
C

$\cos^{- 1} \sqrt{3}$
D

$\sin^{- 1} \frac{1}{\sqrt{3}}$

Solution

By using $μ = \tan θ_{p} \Rightarrow μ = \tan 60^{0} = \sqrt{3}$
$also C = \sin^{- 1} (\frac{1}{μ}) \Rightarrow C = \sin^{- 1} (\frac{1}{\sqrt{3}})$

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