Q.

The angle of a prism is 60° and its refractive index is 2. The angle of minimum deviation suffered by a ray of light in passing through it is

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a

About 20∘

b

30∘

c

60∘

d

45∘

answer is B.

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Detailed Solution

μ=sinA+δm2sinA2⇒2=sin60+δm2sin602 ⇒2×sin30=sin60+δm2⇒sin45∘ =sin60+δm2⇒δm=30∘
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The angle of a prism is 60° and its refractive index is 2. The angle of minimum deviation suffered by a ray of light in passing through it is