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The angle of projection, of which the horizontal range and maximum height of projectile are equal is

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a
45∘
b
θ=tan−1⁡(0⋅25)
c
θ=tan−1⁡4
d
60∘

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detailed solution

Correct option is C

We know thatR=u2sin⁡2θg  and hmax=u2sin2⁡θ2gGiven that R=hmax∴ u2sin⁡2θg=u2sin2⁡θ2g or  2sin⁡θcos⁡θ=sin2⁡θ/2 or  tan⁡θ=4  or θ=tan−1⁡(4)


Similar Questions

Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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