The angle of projection at which the horizontal range and the maximum height of a projectile are equal is

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300

450

600

760

answer is D.

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Detailed Solution

H=R {given} ⇒ u2sin2θ2g=u2sin2θg ⇒ sin2θ=2(2sinθcosθ) {sinθ≠0} ⇒ sinθ=4cosθ ⇒ tanθ=4 ⇒ ∵θ=tan−14=75.960≈760

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