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Questions  

The angle of 1"  (second of arc) in radians is  (Given  3600=2π  rad,  10=60'  and  1'=60")

a
1.745×10−2  rad
b
2.91×10−4  rad
c
4.85×10−6  rad
d
3.42×10−3  rad

detailed solution

Correct option is C

Given, 3600=2π  rad10=(π180)rad=1.745×10−2  rad10=60'=1.745×10−2 rad1'=2.90  s×10−4  rad≈2.91×10−4  rad1'=60"=2.908×10−4  rad1"=4.87×10−4  rad≈4.85×10−6  rad

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