First slide

Electric dipole

Question

The angle $θ$ such that the electric field (vector) at A is perpendicular to dipole moment (vector) is

Moderate

A

0^o
B

90^o
C

$\tan^{- 1} 2$
D

$\tan^{- 1} \sqrt{2}$

Solution

$\tan α = \frac{E_{θ}}{E_{r}} = \frac{1}{2} \tan θ$
$θ + α = \frac{π}{2} \Rightarrow \tan θ = \sqrt{2}$

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