First slide

Electric dipole

Question

The angle θ such that the electric field (vector) at A is perpendicular to dipole moment (vector) is

Moderate

A

0^o
B

90^o
C

tan^-12
D

$\large {\tan ^{ - 1}}\sqrt 2 \$

Solution

$\large tan \alpha = \frac{{_{{E_e}}}}{{{E_r}}} = \frac{1}{2}\tan \theta$
$\large \theta + \alpha = \frac{\pi }{2} \Rightarrow \tan \theta = \sqrt 2 \$

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