The angle at which a ray of light be incident on the face of a glass prism of refracting angle 600 such that it suffers total internal reflection at the other face is (approx) (μ of glass = 1.524 ) take θ= sin-111.524=41 and sin19=0.325

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answer is C.

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Detailed Solution

μ2sinr2=μ1sini2 1.524sinr2=1 sin90 r2=sin-111.524=41 A=r1+r2 60=r1+41 r1=19 μ1sini1=μ2sinr1 (1)sini1=1.524sin19 i1=sin-10.496≈30

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