First slide

Prism

Question

The angle at which a ray of light be incident on the face of a glass prism of refracting angle $60^{0}$ such that it suffers total internal reflection at the other face is (approx) $(μ$ of glass = $1.524$ ) $(t a k e θ = \sin^{- 1} (\frac{1}{1.524}) = 41 a n d \sin 19 = 0.325)$

Moderate

A

0
B

45
C

30
D

60

Solution

$μ_{2} \sin r_{2} = μ_{1} \sin i_{2} 1.524 \sin r_{2} = 1 \sin 90 r_{2} = \sin^{- 1} (\frac{1}{1.524}) = 41 A = r_{1} + r_{2} 60 = r_{1} + 41 r_{1} = 19 μ_{1} \sin i_{1} = μ_{2} \sin r_{1} (1) \sin i_{1} = 1.524 \sin 19 i_{1} = \sin^{- 1} (0.496) \approx 30$

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