The angle at which a ray of light be incident on the face of a glass prism of refracting angle 600 such that it suffers total internal reflection at the other face is (μ of glass = 2 )

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sin−1(12sin150)

sin−1(3sin150)

sin−1(2sin150)

sin−1(sin150)

answer is C.

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Detailed Solution

μ2sinr2=μ1sini2 2sinr2=1 sin90 r2=sin-112=45 A=r1+r2 60=r1+45 r1=15 μ1sini1=μ2sinr1 (1)sini1=2sin15 i1=sin-12sin15

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