Download the app

Questions  

The angle which the velocity vector of a projectile thrown with a velocity v at an angle θ to the horizontal will make with the horizontal after time t of its being thrown up is

a
θ
b
tan−1⁡(θ/t)
c
tan−1⁡Vcos⁡θVsin⁡θ−gt
d
tan−1⁡vsin⁡θ−gtvcos⁡θ

detailed solution

Correct option is D

See fig. (5). Here v′cos⁡α=vcos⁡θand  v′sin⁡α=vsin⁡θ−gt∴ V′sin⁡αV′cos⁡α=Vsin⁡θ−gtVcos⁡θ or  tan⁡α=Vsin⁡θ−gtVcos⁡θα=tan−1⁡(Vsin⁡θ−gt)Vcos⁡θ

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


phone icon
whats app icon