First slide
Projectile motion
Question

The angle which the velocity vector of a projectile thrown with a velocity v  at an angle θ  to the horizontal will make with the horizontal after time t  of its being thrown up is:

Moderate
Solution

 

υ'cosα=υcosθ

And υ'sinα=υsinθgt

 υ'sinαυ'cosα=υsinθgtυcosθ

or tanα=υsinθgtυcosθ

 α=tan1(υsinθgtυcosθ)=tan1(vsinθgtvcosθ)

 

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