The angle which the velocity vector of a projectile thrown with a velocity u at an angle θ to the horizontal will make with the horizontal after time t of its being thrown up is
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a
θ
b
tan-1(θt)
c
tan-1(v cos θv sin θ -gt)
d
tan-1(v sin θ - gtv cos θ)
answer is D.
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Detailed Solution
According to figure v'cos α = v cos θ and v' sin α = v sin θ-gt∴ v' sinαv' cos α = v sin θ - gtv cos θor tan α = v sinθ - gtv cos θ∴ θ = tan-1(v sin θ - gtv cos θ)