Q.

The angle which the velocity vector of a projectile thrown with a velocity u at an angle θ to the horizontal will make with the horizontal after time t of its being thrown up is

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a

θ

b

tan-1(θt)

c

tan-1(v cos θv sin θ -gt)

d

tan-1(v sin θ - gtv cos θ)

answer is D.

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Detailed Solution

According to figure v'cos α = v cos θ and v' sin α = v sin θ-gt∴  v' sinαv' cos α = v sin θ - gtv cos θor tan α = v sinθ - gtv cos θ∴ θ = tan-1(v sin θ - gtv cos θ)
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