Questions
For angles of projection of a projectile at angles , the horizontal range described by the projectile are in the ratio of
detailed solution
Correct option is B
Horizontal range, R=u2sin2θgFor angle of projection 45∘−θ, the horizontal range is :R1=u2sin245∘−θg=R1=u2sin90∘−2θg=u2cos2θgFor angle of projection 45∘+θ, the horizontal range is :R2=u2sin245∘+θg=u2sin90∘+2θg=u2cos2θg∴R1R2=u2cos2θ/gu2cos2θ/g=11.Talk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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