The angles which a vector i^+j^+2k^ makes with X , Y and Z axes respectively are
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a
60∘,60∘,60∘
b
45∘,45∘,45∘
c
60∘,60∘,45∘
d
45∘,45∘,60∘
answer is C.
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Detailed Solution
R→=i^+j^+2k^ Comparing the given vector with R→=Rxi^+Ryj^+Rzk^Rx=1,Ry=1,Rz=2 and |R→|=Rx2+Ry2+Rz2=2cosα=RxR=12⇒α=60∘cosβ=RyR=12⇒β=60∘cosγ=RzR=12⇒γ=45∘