The angular acceleration of a particle moving along a circle is given by α=ksin⁡θ, where θ is the angle turned by particle and k is constant. The centripetal acceleration of the particle in terms of k,θ and R (radius of circle) is given by :

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

2kRsin2⁡θ

2kR(sin⁡θ)

2kR(1+cos⁡θ)

2kR(1−cos⁡θ)

answer is D.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

α=ksin⁡θ∫ωdω=∫ksin⁡θdθω22=−[kcos⁡θ]0θ⇒ω22=−k[cos⁡θ−1]ω2=2k(1−cos⁡θ)ac=ω2R=2kR(1−cos⁡θ)

Watch 3-min video & get full concept clarity