The angular acceleration of a particle moving along a circle is given by α=ksin⁡θ, where θ is the angle turned by particle and k is constant. The centripetal acceleration of the particle in terms of k,θ and R (radius of circle) is given by :

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2kRsin2⁡θ

2kR(sin⁡θ)

2kR(1+cos⁡θ)

2kR(1−cos⁡θ)

answer is D.

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Detailed Solution

α=ksin⁡θ∫ωdω=∫ksin⁡θdθω22=−[kcos⁡θ]0θ⇒ω22=−k[cos⁡θ−1]ω2=2k(1−cos⁡θ)ac=ω2R=2kR(1−cos⁡θ)

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