First slide

Simple hormonic motion

Question

The angular frequency of a simple pendulum is $ω$ rad/sec. Now if the length is made one fourth of the original length, the angular frequency becomes

Easy

A

$ω / 2$
B

$2 ω$
C

$4ω$
D

$ω$

Solution

$T = 2 π \sqrt{(\frac{l}{g})} or ω = \frac{2 π}{T} = \sqrt{(\frac{g}{l})} Further . ω_{1} = \sqrt{(\frac{g}{l / 4})} = 2 \sqrt{(\frac{g}{i})} = 2 ω$

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