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The angular momentum of the disc which spins with ω=3vRk^ and its CM moves with a velocity v=vi^ about O will be

a
3mvR2k^
b
mvR2k^
c
−3mvR2k^
d
−mvR2k^

detailed solution

Correct option is B

The angular momentum of the disc about O isL→O=mr→C×v→C+ICω→=m(xi^+Rj^)×vi^+12mR23vRk^=m(xi^+Rj^)×vi^+12mR23vRk^=mvR(j^×i^)+32mvRk^=−mvRk^+32mvRk^=mvR2k^

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