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The angular momentum of a particle about origin is varying as $L = 4 t + 8$ (SI units) when it moves along a straight line $y = x - 4$ (x,y in meters). The magnitude of force acting on the particle would be :

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Correct option is C

τ=dLdt=4 y=x-4If x=0 then y=-4If x=4 then y=0slope =1From figure r⊥=22Hence τ=r⊥F4=22.F ∴F=2N

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The angular momentum of a particle about origin is varying as L=4t+8 (SI units) when it moves along a straight line y=x−4 (x,y in meters). The magnitude of force acting on the particle would be :

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The angular momentum of a particle about origin is varying as $L = 4 t + 8$ (SI units) when it moves along a straight line $y = x - 4$ (x,y in meters). The magnitude of force acting on the particle would be :