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Q.

The angular momentum of a particle performing uniform circular motion is L. If the kinetic energy of particle is doubled and frequency is halved, then angular momentum becomes

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a

L2

b

2L

c

L4

d

4L

answer is D.

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Detailed Solution

L=Iω K=12Iω2 2K=12I′ω22;12=II′(4) I′=8I;L=(8I)ω2=4Iω⇒L=4L
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