Q.
The angular momentum of a particle performing uniform circular motion is L. If the kinetic energy of particle is doubled and frequency is halved, then angular momentum becomes
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a
L2
b
2L
c
L4
d
4L
answer is D.
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Detailed Solution
L=Iω K=12Iω2 2K=12I′ω22;12=II′(4) I′=8I;L=(8I)ω2=4Iω⇒L=4L
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