The angular momentum of a particle performing uniform circular motion is L. If the kinetic energy of particle is doubled and frequency is halved, then angular momentum becomes

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answer is D.

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Detailed Solution

L=Iω K=12Iω2 2K=12I′ω22;12=II′(4) I′=8I;L=(8I)ω2=4Iω⇒L=4L

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