The angular momentum of a planet of mass M moving around the sun in an elliptical orbit is L→ . The magnitude of the areal velocity of the planet is:

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2LM

L2M

4LM

answer is C.

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Detailed Solution

Assuming SAB a triangle A=12r2θ ⇒dAdt=12r2dθdt ⇒dAdt=12r2ω Now, Angular Momentum, L=Iω=Mr2ω ⇒r2ω=LM Thus , dAdt=12LM ⇒Areal velocity=dAdt=L2M

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