Angular momentum

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Question

The angular momentum of a rigid body of mass m about an axis is n times the linear momentum (P) of the body. Total kinetic energy of the rigid body is:

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Solution

$L = nP KE = {KE}_{R} + {KE}_{T}$
$\begin{array}{l} = \frac{L^{2}}{2 I} + \frac{P^{2}}{2 m} \\ = \frac{n^{2} P^{2}}{2 I} + \frac{P^{2}}{2 m} \\ = \frac{P^{2}}{2} (\frac{n^{2}}{I} + \frac{1}{m}) \end{array}$
NOTE: According to the solution None of the options were matching in the original question. Here we changed the option 1 for the conevenience of the student.

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Angular momentum

Remember concepts with our Masterclasses.

The angular momentum of a rigid body of mass m about an axis is n times the linear momentum (P) of the body. Total kinetic energy of the rigid body is:

L = nP KE = KER + KET =L22I + P22m=n2P22I + P22m=P22 n2I + 1mNOTE: According to the solution None of the options were matching in the original question. Here we changed the option 1 for the conevenience of the student.

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