The angular speed of earth, so that the object on equator may appear weightless, is (g=10 m/s2, radius of earth 6400 km)

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1.25×10−3rad/sec

1.56×10−3rad/sec

1.25×10−1rad/sec

1.56 rad/sec

answer is A.

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Detailed Solution

For condition of weightlessness of equator ω=gR=1800=1.25×10−3rads

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