The angular speed of truck wheel is increased from 900 rpm to 2460 rpm in 26 seconds. The number of revolutions by the truck engine during this time is _____.(Assuming the acceleration to be uniform).
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answer is 728.
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Detailed Solution
θ=ω1+ω22t When it moves with uniform angular acceleration =900×2π60+2460×2π60226 ∴ Number of revolution n=θ2π =900+246060×22π262π =728