The angular velocities of three bodies in simple harmonic motion are ω1, ω2, ω3 with their respective amplitudes as A1, A2, A3 . If all the three bodies have same mass and velocity, then

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A1ω1=A2ω2=A3ω3

A1ω12=A2ω22=A3ω32

A12ω1=A22ω2=A32ω3

A12ω12=A22ω22=A2

answer is A.

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Detailed Solution

Velocity is same. So by using v=Aω⇒A1ω1=A2ω2=A3ω3

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