The angular velocity and the amplitude of a simple pendulum is ω and a respectively. At a displacement X from the mean position if its kinetic energy is T and potential energy is V, then the ratio of T to V is

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X2ω2/(a2−X2ω2)

X2/(a2−X2)

(a2−X2ω2)/X2ω2

(a2−X2)/X2

answer is D.

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Detailed Solution

Kinetic energy T=12mω2(a2−x2)and potential energy, V=12mω2x2 ∴TV=a2−x2x2

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