The angular velocity of the earth with which it has to rotate so that the acceleration due to gravity on 60° latitude becomes zero

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2.5×10-3 rad s-1

1.5×10-3 rad s-1

4.5×10-3 rad s-1

0.5×10-3 rad s-1

answer is A.

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Detailed Solution

gλ=g−Rω2cos2λ,givenλ=600 ⇒0=g−Rω2cos260 ⇒g=Rω2122 ⇒10=6400×1000×ω24 ⇒ω2=1160000⇒ω=1160000=1400=0.25×10-2=2.5×10-3rad/s

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