Q.
Angular velocity of electron in the ground state of Hydrogen atom is ω0.Then what will be the angular velocity of electron in the second excited state of He+ atom?
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a
2ω09
b
9ω016
c
4ω027
d
3ω04
answer is C.
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Detailed Solution
mvr=mωr2=n.h2π⇒ω∝nr2Also, r=r0.n2z combining, ω∝z2n3∴ωHeωH=212x1333⇒ωHe=4ω027
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