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Q.

The angular velocity of a rotating disc decreases linearly with angular displacement from 60 revolutions per minute to zero during 10 revolutions as shown. The angular velocity of the disc 3 seconds after it begins to slow down is

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a

20π10

b

17π10

c

10π17

d

10π13

answer is B.

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Detailed Solution

As ω2−ω02=2αθ⇒​02−2π×60602=2×α×2π×10​⇒α=π/10 radian /sec2​Now,  ω=ω0+αt=2π×6060−π10×3=17π10rad/sec2
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