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Q.

Angular width of central maxima in the Fraunhofer diffraction pattern of a slit is measured. The slit is illuminated by light of wavelength 6000 Å. When the slit is illuminated by light of another wavelength, the angular width decreases by 30%. The wavelength of this light will be

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a

6000 Å

b

4200Å

c

3000 Å

d

1800 Å

answer is B.

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Detailed Solution

Angular width β=2λd⇒β1β2=λ1λ2⇒β70100β=6000λ2⇒λ2=4200Å
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