First slide

Diffraction of light-Wave Optics

Question

Angular width of central maxima in the Fraunhoffer diffraction pattern of a slit is measured. The slit is illuminated by light of wavelength 6000 $\overset{0}{A}$ . When the slit is illuminated by light of another wavelength, the angular width decreases by 30%. The wavelength of this light will be

Moderate

A

6000 Å
B

4200 Å
C

3000 Å
D

1800 Å

Solution

Angular width $β = \frac{2 λ}{d} \Rightarrow β \propto λ$
$\Rightarrow \frac{β_{1}}{β_{2}} = \frac{λ_{1}}{λ_{2}} \Rightarrow \frac{β}{\frac{70}{100} β} = \frac{6000}{λ_{2}} \Rightarrow λ_{2} = 4200 \overset{0}{A}$

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