First slide

Bohr Model of the Hydrogen atom.

Question

In any Bohr orbit of the hydrogen atom, the ratio of kinetic energy to potential energy of the electron is

Easy

A

½
B

2
C

-½
D

-2

Solution

$K . E = \frac{{kZe}^{2}}{2 r} and P . E = - \frac{{kZe}^{2}}{r}; ∴ \frac{K . E .}{P . E .} = - \frac{1}{2}$

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