For any S.H.M., amplitude is 6 cm. If instantaneous potential energy is half the total energy then distance of particle from its mean position is

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3 cm

4.2 cm

5.8 cm

6 cm

answer is B.

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Detailed Solution

If at any instant displacement is y then it is given that U=12×E ⇒12mω2y2=12×12mω2a2⇒y=a2=62=4.2 cm

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