For any two vectors A→ and B→ if A→.B→=|A→×B→| , the magnitude of C→=A→+B→ is equal to:
A2+B2
A+B
A2+B2+AB2
A2+B2+2AB
Given A→.B→=|A→×B→|
Or ABcosθ=ABsinθ
Or cosθ=sinθ
Or θ=450
The magnitude of C→ is
C=A2+B2+2ABcos450
=A2+B2+2AB