First slide

Electrical power

Question

A22O volt,7000 watt bulb is connected across a 110 volt mains supply. The power consumed will be

Moderate

A

1000 watt
B

750 watt
C

500 watt
D

250 watt

Solution

$R = \frac{V^{2}}{P} = \frac{(220)^{2}}{1000} Ω$
Now $P = \frac{V^{2}}{R} = \frac{(110)^{2}}{[(220)^{2} / 1000]} = \frac{(110)^{2} \times 1000}{(220)^{2}}$
= 250 W

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