Apiece of metal weight 46 gm in air, when it is immersed in the liquid of specific gravity 1.24 at 27oC it weighs 30 gm. When the temperature of liquid is raised to 42oC the metal piece weight 30.5 gm, specific gravity of the liquid at 42oC is 1.20, then the linear expansion of the metal will be
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
3.316×10−5/∘C
b
2.316×10−5/∘C
c
4.316×10−5/∘C
d
None of these
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Loss of weight at 27"C is =46−30=16=V1×1.24ρl×g …………..(i)Loss of weight at 42"C is =46−30.5=15.5=V2×1.2ρl×g ………..(ii)Now dividing (i) by (ii), we get 1615.5=V1V2×1.241.2But V1V2=1+3αt2−t1=15.5×1.2416×1.2=1.001042⇒ 3α42∘−27∘=0.001042⇒α=2.316×10−5/∘C
Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!
Apiece of metal weight 46 gm in air, when it is immersed in the liquid of specific gravity 1.24 at 27oC it weighs 30 gm. When the temperature of liquid is raised to 42oC the metal piece weight 30.5 gm, specific gravity of the liquid at 42oC is 1.20, then the linear expansion of the metal will be