Q.

The apparent frequency of a note, when a listener moves towards a stationary source, with velocity of 40 m/s is 200Hz. When he moves away from the same source with the same speed, the apparent frequency of the same note is 160 Hz. The velocity of sound in air is (in m/s)

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a

360

b

330

c

320

d

340

answer is A.

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Detailed Solution

When a listener moves towards a stationary source apparent frequencyn' = (v+v0v)n = 200-----------(i)When listener moves away from the same sourcen'' = (v-v0)vn = 160---------(ii)From (i) and (ii)v+v0v-v0=200160  ⇒v+v0v-v0= 54 ⇒v =360 m/sec
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