Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The apparent frequency of a note, when a listener moves towards a stationary source, with velocity of 40 m/s is 200Hz. When he moves away from the same source with the same speed, the apparent frequency of the same note is 160 Hz. The velocity of sound in air is (in m/s)

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

360

b

330

c

320

d

340

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

When a listener moves towards a stationary source apparent frequencyn' = (v+v0v)n = 200-----------(i)When listener moves away from the same sourcen'' = (v-v0)vn = 160---------(ii)From (i) and (ii)v+v0v-v0=200160  ⇒v+v0v-v0= 54 ⇒v =360 m/sec
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
personalised 1:1 online tutoring