The apparent frequency of a note, when a listener moves towards a stationary source, with velocity of 40 m/s is 200Hz. When he moves away from the same source with the same speed, the apparent frequency of the same note is 160 Hz. The velocity of sound in air is (in m/s)
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a
360
b
330
c
320
d
340
answer is A.
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Detailed Solution
When a listener moves towards a stationary source apparent frequencyn' = (v+v0v)n = 200-----------(i)When listener moves away from the same sourcen'' = (v-v0)vn = 160---------(ii)From (i) and (ii)v+v0v-v0=200160 ⇒v+v0v-v0= 54 ⇒v =360 m/sec
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The apparent frequency of a note, when a listener moves towards a stationary source, with velocity of 40 m/s is 200Hz. When he moves away from the same source with the same speed, the apparent frequency of the same note is 160 Hz. The velocity of sound in air is (in m/s)