The apparent weight of man inside a lift moving up with certain acceleration is 900N. When the lift is coming down with the same acceleration apparent weight is found to be 300N. The mass of the man is (g=10ms−2)
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a
45 kg
b
60 kg
c
75 kg
d
80 kg
answer is B.
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Detailed Solution
T-mg=ma 900-mg=ma---(1) mg-T=ma mg-300=ma----(2) from (1) & (2) we get 2mg=1200 mg=600 m=60kg