First slide
Application of Newtons laws
Question

The apparent weight of man inside a lift moving up with certain acceleration is 900N. When the lift is coming down with the same acceleration apparent weight is found to be 300N. The mass of the man is (g=10ms2)

Moderate
Solution

 

T-mg=ma 900-mg=ma---(1) mg-T=ma mg-300=ma----(2) from (1) & (2) we get 2mg=1200

   mg=600

      m=60kg

 

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