First slide

Rectifiers

Question

The applied input AC power to a full wave rectifier is 80 W and DC output power obtained is 60 W . The rectification efficiency is $χ$ then $χ$ is

Moderate

A

00.70
B

00.75
C

00.80
D

00.85

Solution

Input AC Power = 80 W
Output DC Power = 60 W
$χ$ = ?
$R e c t i f i c a t i o n E f f i c i e n c y : χ = \frac{O u t p u t D C P o w e r}{I n p u t A C P o w e r} = \frac{60}{80} = \frac{3}{4} = 0.75$

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