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Q.

The applied input AC power to a full wave rectifier is 80 W  and DC output power obtained is 60 W . The rectification efficiency is χ  then χ is

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a

00.70

b

00.75

c

00.80

d

00.85

answer is B.

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Detailed Solution

Input  AC Power = 80 WOutput DC  Power = 60 W   χ = ?   Rectification Efficiency :  χ=Output DC  PowerInput  AC Power = 6080=34=0.75
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