Q.

The approximate wavelength of a photon of energy 2.48 eV is

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a

500  Ao

b

5000  Ao

c

2000  Ao

d

1000  Ao

answer is B.

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Detailed Solution

By  using EeV=12375λAo⇒λ=123752.48=4989.9Ao≈5000Ao
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