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An arc of a circle of radius R subtends an angle $\frac{π}{2}$ at the centre. It carries a current i. The magnetic field at the centre will be

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μ0i2R

μ0i8R

μ0i4R

2μ0i5R

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detailed solution

Correct option is B

B= μ04π θir = μ04π × π2 × iR = μ0i8R

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An arc of a circle of radius R subtends an angle π2 at the centre. It carries a current i. The magnetic field at the centre will be

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An arc of a circle of radius R subtends an angle $\frac{π}{2}$ at the centre. It carries a current i. The magnetic field at the centre will be