First slide

Pontial due to

Question

An arc of radius R is shown in the figure, find the potential at its centre :

Difficult

A

$\frac{10 kQ}{R}$
B

$\frac{5 kQ}{R}$
C

$\frac{\sqrt{3} k Q}{R}$
D

$\frac{\sqrt{2} k Q}{R}$

Solution

$V = \frac{k (10 Q)}{R} = \frac{10 kQ}{R}$
(potential is scalar)

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