An area of cross-section of rubber string is 2 cm2. Its length is doubled when stretched with a linear force of 2×105 dynes. The Young's modulus of the rubber in dyne/cm2 will be
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a
4×105
b
1×105
c
2×105
d
1×104
answer is B.
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Detailed Solution
If length of the wire is doubled then strain = 1∴Y= Stress = Force Area =2×1052=105 dyne cm2