First slide
Elastic behaviour of solids
Question

An area of cross-section of rubber string is  2 cm2. Its length is doubled when stretched with a linear force of 2×105 dynes. The Young's modulus of the rubber in  dyne/cm2 will be

Moderate
Solution

If length of the wire is doubled then strain = 1

Y= Stress = Force  Area =2×1052=105 dyne cm2

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App