The area of cross-section of a wire is 10−5m2 when its length is increased by 0.2% a tension of 250N is produced. The Young's modulus of the wire will be ........

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9.5×109Nm−2

11.5×109Nm−2

12.5×109Nm−2

10.5×109Nm−2

answer is C.

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Detailed Solution

y=FLAΔL=F/AAL/L y=250/10−50.2/100=2500.2×10010−5=12.5×109

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