First slide

Accuracy; precision of instruments and errors in measurements

Question

The area enclosed by a circle of diameter 1.06 m to correct number of significant figures is

Moderate

A

$0.88 m^{2}$
B

$0.088 m^{2}$
C

$0.882 m^{2}$
D

$0.530 m^{2}$

Solution

Here, $r = \frac{1.06}{2} = 0.530 m$
Area enclosed $= π r^{2} = 3.14 {(0.53)}^{2}$
$= 0.882026 m^{2} = 0.882 m^{2}$
(rounded to three significant figures)

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