The area of a parallelogram formed from the vectors A→=i^−2j^+3k^ and B→=3i^−2j^+k^ as adjacent sides is

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83 units

64 units

32 units

46 units

answer is D.

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Detailed Solution

A→=i^−2j^+3k^ and B→=3i^−2j^+k^ Area of parallelogram =|A→×B→| Now, A→×B→=|i^j^k^1−233−21|=4i^+8j^+4k^ |A→×B→|=42+82+42=96=46 units .

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