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Q.

The area of the plates of a parallel plate condenser is A and the distance between the plates is 10 mm. There are two dielectric sheets in it, one of dielectric constant 10 and thickness 6 mm and the other of dielectric constant 5 and thickness 4 mm. The capacity of the condenser is

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a

1235ε0A

b

23ε0A

c

50007ε0A

d

1500 ε0A

answer is C.

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Detailed Solution

C=ε0At1k1+t2k2=ε0A6×10−310+4×10−35=50007ε0A
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